Keep in mind that air naturally contains around 300 ppm of CO 2 and that the target for maximizing plant growth is within 1200 ppm to 1500 ppm.
#How to calculate ppm of co2 in room generator#
Physical workers usually do not carry more than 4,000 kg per 8-hr shift, so one person would need at least 5 days to carry out just the lifting work. Calculate the time that your CO 2 generator must run to reach the optimal level of carbon dioxide in your culture room. Therefore, we need 7.5 billion of such trucks, in order to go back to the safe Carbon level. Amount enough to fill a 20-ft container truck! If we would relate that amount to standard cement bags, each of us would need to take care of 687 (25 kg) bags. If we understand that there are 7.5 billion people on this planet, and we task each person to take care of his or her own portion, each person would need to sequester around 17,165 kg of Carbon. Saying 128.74 Giga-tonnes of carbon sounds quite abstract and does not mean much. In order to go back to the safe level of 350 ppmv, we would need to sequester 128.74 GtC
At that time, the CO2 level was around 280 ppmv, or, in other words, since pre-industrial times, human influence has added 130.28, which equates to 278.24 Giga tonnes of Carbon ((410.28-280) * 2.1357 GtC per ppmv ). We will take the year 1800 as the comparison point for pre-industrial CO2 concentration in the atmosphere. Let’s now consider how much CO2 or Carbon we have added since the Industrial Revolution and how much carbon we need to sequester, in order to reach what is considered the stable level of 350ppmv. This will give us 0.0623240117 m% CO2.įurthermore, multiplying Earth’s atmosphere 5.137 × 10^15 tonnes * 0.0623240117 m% CO2, we will see that the total weight of CO2 in the atmosphere is ~3,208 Gt CO2.Īs the carbon content in carbon dioxide is 27.3%, that also means that each 1 ppmv (part per million of volume) of the atmosphere weighs approximately 2.1357 Gt of Carbon.Īs I said, current CO2 levels have reached the dangerously high 410.28 ppmv, and it is said that if we reach 450ppmv there is a 50% chance that we will reach 2C, which many call the point of no return. Now, we can calculate the following: 0.041028% (CO2 atmosphere volume) * 28.971 g/mole (average molar mass of dry air) / 44.0087 g (CO2). If we take the highest measured concentration of CO2 as 410.28 ppmv, the percentage content would be equal to 0.041028%. We can calculate that 1 mole of CO2 has a weight of 44.0087 grams equation (1)) carbon dioxide concentration for the room. Mol is is defined as the amount of a chemical substance that contains as many representative particles (atoms, molecules, ions, electrons, or photons) as there are atoms in 12 grams of carbon-12 therefore, one mole has 12.011 g C, and 1 gram of carbon has 0.083257 mole. the quantity of carbon dioxide in a million particles of air ppm (particle per million). Let’s start from the mass of the Earth atmosphere, which is 5.137 × 10^15 tonnes
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